.67x^2+35=87

Solution for .67x^2+35=87 equation:

.67x^2+35=87

We move all terms to the left:

.67x^2+35-(87)=0

We add all the numbers together, and all the variables

.67x^2-52=0

a = .67; b = 0; c = -52;
Δ = b2-4ac
Δ = 02-4·.67·(-52)
Δ = 139.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{139.36}}{2*.67}=\frac{0-\sqrt{139.36}}{1.34}
=-\frac{\sqrt{}}{1.34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{139.36}}{2*.67}=\frac{0+\sqrt{139.36}}{1.34}
=\frac{\sqrt{}}{1.34}
$